hess' law problems

0 ΔH  =-94.5 kJ 0000002145 00000 n C 2 H 6 ( g )                                                           ”H   = - 9 4 . answer = 72 kJ, (5)  Find the ΔH for the reaction below, 10Cl 2(g)         ΔH = -65 kJ →    … 0000001699 00000 n 0000002778 00000 n 1. Hess's Law Problem Set (1) Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: 2CO2(g) + H2O(g) → C 2H2(g) + 5/2O2(g) NO(g) + NO2(g) + Na2O(s) They will not be collected, nor will these particular questions be asked on an exam. 0000010334 00000 n %%EOF 0000001957 00000 n 37 0 obj <>/Filter/FlateDecode/ID[<88C44B4DC3E04C85CC831225E51EB857>]/Index[26 25]/Info 25 0 R/Length 68/Prev 23483/Root 27 0 R/Size 51/Type/XRef/W[1 2 1]>>stream 0000124974 00000 n 0000003611 00000 n N " $ & ( J L P P l ¬ ® � „! ΔH = 849 kJ (Note that the first bit of data is associated with the reactant (benzene) while the last two are associated with the products (CO2 produced when C combusts and H2O produced when H2 is combusted. That gets H2O on the left-hand side and the 6 will cancel the 6H2O in the second equation. 6 ϊ ό $ ( * , B D P R T V f h z | ~ € β δ ψ ϊ Be aware of this practice (one with which I disagree). 0000013546 00000 n @� /�4 H2(g) + 1/2O2(g)  →  H2O(g)                                4PCl5(g)  →  P4(s)  +  Chemistry 120 Hess’s Law Worksheet 1. ΔH = -402.5 kJ 2CO2(g)  +  H2O(g)  →  0000012599 00000 n 2(g), N2(g)  +  3H2(g)  →  2 O(l)  +  Cl2(g)                              0000017277 00000 n 0000047547 00000 n 2 C 2 H 6 O ( l ) +   O 2 ( g ) C 2 H 6 O ( l )   +   3 O 2 ( g )   ’! C 2H6(g) + 7/2O2(g)            →  ZnSO4(s). Hess's Law Worksheet ‐ answers 1. (1) Find the ΔH for the reaction below, given the following reactions and subsequent ΔH values: 50 0 obj <>stream 1/2H2(g)  +  1/2Cl2(g)  %PDF-1.4 %���� 2 C O 2 ( g )   +   2 H 2 O ( l )                 ”H = - 5 8 3 . H 2 O ( g )                                                                                                           ”H = 4 4 k J a n s w e r = 7 2 k J   ( 5 )   F i n d t h e ”H f o r t h e r e a c t i o n b e l o w , g i v e n t h e f o l l o w i n g r e a c t i o n s a n d s u b s e q u e n t ”H v a l u e s : 2 C 2 H 4 O ( l ) + 2 H 2 O ( l )   ’! Notice that I'm not paying any attention to N2 or O2. 1) Let's get a balanced equation for our target equation: 2) Rearrange the three data equations so that, when added, they give the target equation: 4) When the three equations are added together, this results in: 5) To get the final answer, divide everything by 3: Calculate the enthalpy change for the reaction: 1) We modify the data equations based on the idea of reproducing the target equation when the data equations are added together. ΰ β ψ ϊ 4 6 N P ” – ¨ � Β Ζ " $ ςγΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΈγΈγΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΔΤΈ¬ hοψ CJ OJ QJ aJ h‡ CJ OJ QJ aJ hU!­ h‡ CJ H*OJ QJ aJ hU!­ h‡ CJ OJ QJ aJ hU!­ hοψ CJ OJ QJ aJ h�y 5�CJ OJ QJ aJ @ . given the following reactions and subsequent ΔH values: 0000002648 00000 n e$�R;����>�_gL�:�d�8vv��p7G��J}A���)��@�����[��iM@�g�Iƾ2�1����Q7�DII"���|���X���#�r�@~�j�5.J�����C�٨����$Ө Lfٴ�G�!3�d�})�[H�u�̑�W�(҇� →    H2SO4(aq)    What is the enthalpy of formation for CH4? %%EOF CH4O(l)  →  CH2O(g) +  N2(g)  +  3H2(g)  →  →  H answer = 886 kJ, (8)  Find the ΔH for the reaction below, ¨ ΔH = 57.5 kJ C H 2 O ( g )   +   N 2 ( g )   +   3 H 2 ( g )                 ”H = - 3 7 k J N 2 ( g )   +   3 H 2 ( g )   ’! NO(g) + NO2(g) → N2O(g) + O2(g)                         12 52 0000061286 00000 n Given the following equations and Ho values, determine the heat of reaction (kJ) at 298 K for the reaction:. v 2C2H4O(l) + 2H2O(l)  →  answer = 249.8 kJ, (2)  Find the ΔH for the reaction below, ΔH = -2439 kJ ]p � [Content_Types].xml �(� ���j�0E����Ѷ�J�(��ɢ�eh��4vD�BR^�Q�������{���`��*[�Қ����p+��K�3�ȟI"3�)k�$kd4��L�B�jJ2�ѽP�4�u`�RY�Y�W_S��/��>�zO�[��2�A��*f�+.

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